The circuit shown here is used to compare the emf's of two cells E 1 and E 2 (E 1 > E 2 ). The null point is at C when the galvanometer is connected to E 1 . When the galvanometer is connected to E 2 , the null point will be –
Text Solution
Verified by ExpertsThe correct answer is:
A
since 
. So, for 
we have 
and hence null point will be obtained at shorter length i.e. to left of C.
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